Posting filepath in file upload control in .NET to the next page and uploading the file from second page
In our application (using C# .NET) there is a form with file upload options. After filling up the form details, the summary of the details need to be shown in the next page before committing the information into the database. Right now, Server.Control is used to transfer the contents to the next page and the form details are retrieved using Request.Form["control id"]. But this is not working for File upload control alone.
File upload can not be done in the first page itself, as the foreign key in File upload table gets updated only in second page after confirmation.
Therefore, is there a way to transfer the entire file path to the next page and retrieve it there so as to upload the file from the second page?
Thanks in advance.
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giridharprasad
7/22/2008 4:32:31 AM
asp.net.web-forms
93655 articles. 
6 followers.
6 Replies
2967 Views
Hi
use session
session["path"]=Fileupload1.PostedFile.FileName
then next page
retrieve the file name
String spath=Session["path"].ToString()
Regards,
M.Venkatesan
My Blog : http://venkat-dotnetsamples.blogspot.com
Please remember to click “Mark as Answer” on the post that helps you,and to click “Unmark as Answer” if a marked post does not actually answer your question.
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venkatu2005
7/22/2008 4:57:19 AM
hi giridharprasad,
u sohuld make use of this function to get the full path rather than only FileUpload1.PostedFile.FileName.
System.IO.Path.GetFullPath(FileUpload1.PostedFile.FileName)
Now if ur using Cross PostBack (using Sever.Transfer) then rather than using Session u can also use HttpContext.Current.Items.Add method
e.g. In case of Cross PastBack
In FirstPage
HttpContext.Current.Items.Add("path", IO.Path.GetFullPath(FileUpload1.PostedFile.FileName))
In Second Page
Dim strPath = HttpContext.Current.Items.Item("path").ToString()
Otherwise u can make use of this also
Session("Path") = IO.Path.GetFullPath(FileUpload1.PostedFile.FileName)
Dim strPath = Session("Path").ToString()
I hope this will help u.
Please mark as Answer if it helps u. Thanks!
Parth Patel
Techsture Technologies
Software Developer
Ahmedabad
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Coool
7/22/2008 5:07:17 AM
Hi
Thanks for the code. Indeed, I require the full file path. When I tried your code, I got an error msg "the name IO does not exist in current context". Please let me know how I should resolve this error.
Thanks
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giridharprasad
7/22/2008 5:46:56 AM
This is the code I am using as per your suggestion in the first page
protected void Issues_submit_Click2(object sender, EventArgs e){
//Session["filename"] = System.IO.Path.GetFullPath(FileUpload1.PostedFile.FileName); //HttpContext.Current.Items.Add("path", IO.Path.GetFullPath(FileUpload1.PostedFile.FileName));Session["filename"] = IO.Path.GetFullPath(FileUpload1.PostedFile.FileName);Server.Transfer("~/Confirmation.aspx",true);}
and I have th following code in Page Load event of next page protected void Page_Load(object sender, EventArgs e){
if (Request.Params.Count > 0){
Issues_confirm_short_desc.Text = Request.Params.Get(
"Issues_issue_name"); //Issues_file_upload.Text = Request.Params.Get("Issues_Field1");Issues_confirm_detailed_desc.Text = Request.Params.Get("Issues_issue_desc");//Issues_file_upload.Text = Session[
"filename"].ToString(); //FileUpload1.PostedFile.FileName = Session["filename"].ToString(); string strPath = Session["Path"].ToString();I am able to retrieve all other values like Issues_confirm_detailed_desc.Text and Request.Params.Get("Issues_issue_desc");
But Iam getting "The name IO does not exist in the current context" in both the cases.
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giridharprasad
7/22/2008 6:15:49 AM
Sorry to post my code in VB.NET,
try
System.IO.Path instead on IO.Path
Please mark as Answer if it helps u. Thanks!
Parth Patel
Techsture Technologies
Software Developer
Ahmedabad
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Coool
7/22/2008 6:30:36 AM
I have used the following code to achieve it
In the first page
Context.Items[
"FileUpload1.PostedFile.FileName"] = System.IO.Path.GetFullPath(FileUpload1.PostedFile.FileName);and in the next page
Strpath = (string)Context.Items["FileUpload1.PostedFile.FileName"];Issues_file_upload.Text = (
string)Strpath;Thanks for helping out
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giridharprasad
7/22/2008 6:55:16 AM
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