XMLHTTP Powerbuilder
I am trying to request a document and using MSXML.4.0 and Keep getting an
error of "external object property" on lole_xml_httpreq.responseText. Is
this not a valid call?
My status is coming back with 200 - a success
oleobject lole_xml_httpreq
long ll_rc
String ls_requeststring
String ls_response
String ls_status
lole_xml_httpreq = CREATE oleobject
ll_rc = lole_xml_httpreq.ConnectToNewObject("MSXML2.XMLHTTP.4.0")
ls_requeststring = "url"
lole_xml_httpreq.open("GET",ls_requeststring,false)
lole_xml_httpreq.send()
ls_status = String(lole_xml_httpreq.status)
Messagebox("status","Status = " + ls_status
ls_response = lole_xml_httpreq.responseText
Messagebox("",ls_response)
Any help would be greatly appreciated,
Thanks,
Jason Jakes
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0 |
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Jason_Jakes
1/16/2003 5:40:00 PM
sybase.ole-ocx-activex
6324 articles. 
0 followers.
2 Replies
1864 Views
On Thu, 16 Jan 2003 12:40:00 -0500, Jason_Jakes wrote:
Jason,
When I was wrapping the MSXML 4.0 services in PB8 I noticed that not
all of the methods/properties that were supposed to be exposed were
actually exposed to PowerBuilder ( for what reason, I am unsure ).
Open the control in the PB Object Browser and verify that the property
that you are trying to access is listed in that screen. If not, it's
probably not being exposed to PB as you expected it.
Another "trick" you can sometimes use, if you have access to Visual
Basic, is open the TypeLib for that control in VB and check out how
the methods/properities are listed there ...
For giggles, I'll test out PB8 on my machine with that control and see
if I can get it to work ... will let you know.
D.
>I am trying to request a document and using MSXML.4.0 and Keep getting an
>error of "external object property" on lole_xml_httpreq.responseText. Is
>this not a valid call?
>
>My status is coming back with 200 - a success
>
>oleobject lole_xml_httpreq
>long ll_rc
>String ls_requeststring
>String ls_response
>String ls_status
>
>lole_xml_httpreq = CREATE oleobject
>
>ll_rc = lole_xml_httpreq.ConnectToNewObject("MSXML2.XMLHTTP.4.0")
>
>ls_requeststring = "url"
>
>lole_xml_httpreq.open("GET",ls_requeststring,false)
>lole_xml_httpreq.send()
>
>ls_status = String(lole_xml_httpreq.status)
>Messagebox("status","Status = " + ls_status
>
>ls_response = lole_xml_httpreq.responseText
>Messagebox("",ls_response)
>
>Any help would be greatly appreciated,
>Thanks,
>Jason Jakes
|
|
0 |
|
Douglas
1/31/2003 3:41:47 PM
On Thu, 16 Jan 2003 12:40:00 -0500, Jason_Jakes wrote:
This is what I tried, and it worked just fine ... perhaps there is a
Case Sensativity issue?
I donno ... here's a copy of my code for you to cut and paste - I just
had it in the click event of a button to mess with ...
D.
----------- Start Code Block -----------------
constant uint S_OK = 0
OLEObject lole_control
long ll_rc
string ls_Request
string ls_Response
string ls_Status
lole_control = Create OLEObject
If ( isValid( lole_control ) ) Then
ll_rc = lole_control.ConnectToNewObject("MSXML2.XMLHTTP.4.0")
If ( ll_rc = S_OK ) Then
ls_Request = 'http://www.google.com'
lole_control.open("GET",ls_request,false)
lole_control.send()
ls_status = string( lole_control.status )
MessageBox("Status Info", ls_status, Information!,
OK!)
ls_Response = lole_control.ResponseText
MessageBox("Response", ls_Response, Information!, OK!)
lole_control.Disconnectobject( )
Else
MessageBox("Error #" + string( ll_rc ), "Failed to
connect to Object: MSXML2.XMLHTTP.4.0", StopSign!, OK!)
End if
Else
MessageBox("Error", "Failed to create OLE Object container!",
StopSign!, OK!)
End if
----------- End Code Block -----------------
>I am trying to request a document and using MSXML.4.0 and Keep getting an
>error of "external object property" on lole_xml_httpreq.responseText. Is
>this not a valid call?
>
>My status is coming back with 200 - a success
>
>oleobject lole_xml_httpreq
>long ll_rc
>String ls_requeststring
>String ls_response
>String ls_status
>
>lole_xml_httpreq = CREATE oleobject
>
>ll_rc = lole_xml_httpreq.ConnectToNewObject("MSXML2.XMLHTTP.4.0")
>
>ls_requeststring = "url"
>
>lole_xml_httpreq.open("GET",ls_requeststring,false)
>lole_xml_httpreq.send()
>
>ls_status = String(lole_xml_httpreq.status)
>Messagebox("status","Status = " + ls_status
>
>ls_response = lole_xml_httpreq.responseText
>Messagebox("",ls_response)
>
>Any help would be greatly appreciated,
>Thanks,
>Jason Jakes
|
|
0 |
|
Douglas
1/31/2003 4:06:40 PM
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