#### is there a support for 128 bit at 64 bit delphi?

```Hi,

There is one bcd number has 20 digit. But it doesn't fit into 64 bit.
It
needs 66 bit to store. Anyway I need to convert this 20 digit number
to hex format. I mean, input is 20 digit bcd number as string, output
should be hexadecimal number as string.

What is the pratical way to do this?

Thank you.
```
 0
Mehmet
2/22/2012 8:32:08 PM

7 Replies
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```> {quote:title=Mehmet Fide wrote:}{quote}
> Hi,
>
> There is one bcd number has 20 digit. But it doesn't fit into 64 bit.
> It
> needs 66 bit to store. Anyway I need to convert this 20 digit number
> to hex format. I mean, input is 20 digit bcd number as string, output
> should be hexadecimal number as string.
>
> What is the pratical way to do this?
>
> Thank you.

Google for BigInteger or BigDecimal Variant Delphi
```
 0
An
2/22/2012 8:52:57 PM
```> Google for BigInteger or BigDecimal Variant Delphi
> Here is one -

Nice library. Thanks for it.
But still I wonder isn't there 128 bit native support in 64 bit mode?
```
 0
Mehmet
2/22/2012 11:30:54 PM
```"Mehmet Fide" wrote
> There is one bcd number has 20 digit. But it doesn't fit into 64 bit.
> It needs 66 bit to store. Anyway I need to convert this 20 digit number
> to hex format. I mean, input is 20 digit bcd number as string, output
> should be hexadecimal number as string.
> What is the practical way to do this?

Mehmet,
If it is just this one case, I would just make a string-in, string-out function
with my own big-integer accumulator from an array of three UInt32
variables and do a multiply x 10 and add for each new input decimal
digit. The second step, shifting the 4-bit nibbles into hexadecimal is
easy.
HTH, JohnH
```
 0
John
2/23/2012 1:50:08 AM
```Mehmet Fide wrote:

> Hi,
>
> There is one bcd number has 20 digit. But it doesn't fit into 64 bit.
> It
> needs 66 bit to store. Anyway I need to convert this 20 digit number
> to hex format. I mean, input is 20 digit bcd number as string, output
> should be hexadecimal number as string.
>
> What is the pratical way to do this?
>
> Thank you.

http://rvelthuis.de/programs/decimals.html

My Decimal type's mantissa can hold 96 bits. Convert the BCD to a
string (this is simple, as each nibble contains one digit), assign it
to a Decimal and get the bytes from the Decimal. These can then be
turned into a hex string again.

How is the BCD stored? Let's assume 10 bytes with the most significant
digit in the top 4 bits of the first byte:

S := '';
for I := 0 to 9 do
S := S + Char(Ord('0') + Bytes[I] shr 4) +
Char(Ord('0') + Bytes[I| and \$0F);

If the order is reverse (most significant digit in last byte), you can
do:

S := '';
for I := 0 to 9 do
S := Char(Ord('0') + Bytes[I] shr 4) +
Char(Ord('0') + Bytes[I| and \$0F) + S;

Now, if you have the number in a string (let's call it S) already, then
you don't need to do any of the above:

var
MyBytes: TBytes;

MyDecimal := S; // converts string representation to Decimal with
// mantissa containing 96 bit number and scale of 0.
MyBytes = MyDecimal.GetBytes; // lower 12 bytes (96 bits) are
mantissa

Now ignore the top Longword and use the remaining 96 bits to get your
hex:

const
HexChars: array[0..15] of Char = '0123456789ABCDEF';
var
Hex: string;

...

Hex := '';
for J := 0 to 11 do
Hex := HexChars[MyBytes[I] shr 4] +
HexChars[MyBytes[I] and \$0F] + Hex;

That will give you a 24 digit hex string.
--
Rudy Velthuis

"He would make a lovely corpse."
-- Charles Dickens (1812-1870)
```
 0
Rudy
2/23/2012 8:00:10 PM
```Rudy Velthuis (TeamB) has brought this to us :
>
> http://rvelthuis.de/programs/decimals.html

Hi,

Thanks a lot, this unit did the job directly :)

{Delphi}
function BytesToHex(aSource: TBytes): string;
begin
SetLength(Result, Length(aSource) * 2);
if Length(aSource) > 0 then
BinToHex(aSource[0], PChar(Result), Length(aSource));
end;

procedure TForm1.Button1Click(Sender: TObject);
Var
D: Decimal;
B: TBytes;
begin
D := '62636944367208999885';
B := D.GetBytes;
end;
{Delphi}
```
 0
Mehmet
2/23/2012 10:39:26 PM
```Mehmet Fide wrote:

> Rudy Velthuis (TeamB) has brought this to us :
> >
> > http://rvelthuis.de/programs/decimals.html
>
> Hi,
>
> Thanks a lot, this unit did the job directly :)
>
> {Delphi}
> function BytesToHex(aSource: TBytes): string;
> begin
>   SetLength(Result, Length(aSource) * 2);
>   if Length(aSource) > 0 then
>     BinToHex(aSource[0], PChar(Result), Length(aSource));
> end;
>
> procedure TForm1.Button1Click(Sender: TObject);
> Var
>   D: Decimal;
>   B: TBytes;
> begin
>  D := '62636944367208999885';
>  B := D.GetBytes;
> end;
> {Delphi}

YAY!

--
Rudy Velthuis [TeamB]        http://rvelthuis.de

"I hear Glenn Hoddle has found God. That must have been one hell
of a pass." -- Bob Davies.
```
 0
Rudy
2/24/2012 10:44:35 AM
```> What is the pratical way to do this?

20 digit binary requires 66 bits. bcd stores 2 digits in one byte. Delphi
supports TBCD type (unit FMTBCD).

the program below runs fine in XE2

program testfmtbcd;

{\$APPTYPE CONSOLE}

{\$R *.res}

uses
System.SysUtils,
fmtbcd,
variants;

var length  : TBCD;
var width   : TBCD;
var height  : TBCD;
var content : TBCD;

var fs      : TFormatSettings;
var v       : variant;

begin
fs                  := TFormatSettings.Create;
fs.DecimalSeparator := '.';

length  := strtoBCD('62636944367208999885' );
width   := strtoBCD('1234567890.123456789', fs ) / 100.0;       // note the decimal point
height  := 987654321098765.4 / 987654.3;
content := length * width * height;

writeln( 'l=' + formatbcd( '##############################.###################', length ));
writeln( 'w=' + formatbcd( '##############################.###################', width  ));
writeln( 'h=' + formatbcd( '##############################.###################', height ));
writeln( 'c=' + formatbcd( '##############################.###################', content ));
if content <> strtobcd( formatbcd( '##############################.###################', content + 1 )) then  // localized decimal point
begin
writeln( '*** The values of content and strtoBCD( formatBCD( ''' + formatbcd( '##############################.###################', content ) + ''')) are different' );
end;

end.
```
 0
2/27/2012 9:21:10 AM

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