How to get 2 decimal places?

I have one session var and value of it will be double.How can i do it to be in 2 decimal places rounded up to nearest 5cents.

eg.21.781 -> 21.10

21.322 -> 21.05

45 -> 45.00

0
myaung
7/1/2008 4:13:12 AM
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Math.Round Method (Decimal, Int32, MidpointRounding)

 

Rounds a decimal value to a specified precision. A parameter specifies how to round the value if it is midway between two other numbers.

Namespace: System

Parameters

d

A decimal number to be rounded.

decimals

The number of significant decimal places (precision) in the return value.

mode

Specification for how to round d if it is midway between two other numbers.

Return Value

The number nearest d with a precision equal to decimals. If d is halfway between two numbers, one of which is even and the other odd, then mode determines which of the two numbers is returned. If the precision of d is less than decimals, then d is returned unchanged.

 

Remarks

The decimals parameter specifies the number of significant decimal places in the return value and ranges from 0 to 28. If decimals is zero, an integer is returned.

The behavior of this method follows IEEE Standard 754, section 4. The kind of rounding that is performed if mode is ToEven is sometimes called rounding to nearest, or banker's rounding.

 

Code Snippet
 
' This example demonstrates the Math.Round() method in conjunction
' with the MidpointRounding enumeration.
Imports System

Class Sample
    Public Shared Sub Main()
        Dim result As Decimal = 0D
        Dim posValue As Decimal = 3.45D
        Dim negValue As Decimal = -3.45D
       
        ' By default, round a positive and a negative value to the nearest even number.
        ' The precision of the result is 1 decimal place.
        result = Math.Round(posValue, 1)
        Console.WriteLine("{0,4} = Math.Round({1,5}, 1)", result, posValue)
        result = Math.Round(negValue, 1)
        Console.WriteLine("{0,4} = Math.Round({1,5}, 1)", result, negValue)
        Console.WriteLine()
       
        ' Round a positive value to the nearest even number, then to the nearest number
        ' away from zero. The precision of the result is 1 decimal place.
        result = Math.Round(posValue, 1, MidpointRounding.ToEven)
        Console.WriteLine("{0,4} = Math.Round({1,5}, 1, MidpointRounding.ToEven)", _
                           result, posValue)
        result = Math.Round(posValue, 1, MidpointRounding.AwayFromZero)
        Console.WriteLine("{0,4} = Math.Round({1,5}, 1, MidpointRounding.AwayFromZero)", _
                           result, posValue)
        Console.WriteLine()
       
        ' Round a negative value to the nearest even number, then to the nearest number
        ' away from zero. The precision of the result is 1 decimal place.
        result = Math.Round(negValue, 1, MidpointRounding.ToEven)
        Console.WriteLine("{0,4} = Math.Round({1,5}, 1, MidpointRounding.ToEven)", _
                            result, negValue)
        result = Math.Round(negValue, 1, MidpointRounding.AwayFromZero)
        Console.WriteLine("{0,4} = Math.Round({1,5}, 1, MidpointRounding.AwayFromZero)", _
                           result, negValue)
        Console.WriteLine()
   
    End Sub 'Main
End Class 'Sample
'
'This code example produces the following results:
'
' 3.4 = Math.Round( 3.45, 1)
'-3.4 = Math.Round(-3.45, 1)
'
' 3.4 = Math.Round( 3.45, 1, MidpointRounding.ToEven)
' 3.5 = Math.Round( 3.45, 1, MidpointRounding.AwayFromZero)
'
'-3.4 = Math.Round(-3.45, 1, MidpointRounding.ToEven)
'-3.5 = Math.Round(-3.45, 1, MidpointRounding.AwayFromZero)
'

Regards,
Punithkumar
0
Punithkumar
7/1/2008 5:07:25 AM

myaung:

I have one session var and value of it will be double.How can i do it to be in 2 decimal places rounded up to nearest 5cents.

eg.21.781 -> 21.10

21.322 -> 21.05

45 -> 45.00

Hi myaung,

Based on your description, you need to format the number in 2 decimal places and rounded it up to nearest 5 cents. But according to your exmaple, I am really confused: I have no idea why 21.781 comes into 21.10 instead of 21.80.

Here I have do a example for you. Have a try on it and tell me is it what you are looking for. 

Function doNum(ByVal n As Double) As String
    doNum = Format(Math.Round(n * 2, 1) / 2, "0.00")
End Function
Best Regards,
Shengqing Yang

Please remember to click “Mark as Answer” on the post that helps you, and to click “Unmark as Answer” if a marked post does not actually answer your question. This can be beneficial to other community members reading the thread : )
0
Shengqing
7/2/2008 7:03:39 AM

 Hi Yang,

sorry for late reply.

As you pointed,21.781 must be 21.80 .

Your function can really help me.

Thanks alot.

With Best Regards,

myaung

0
myaung
7/2/2008 3:14:36 PM
Reply:

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