'System.Web.UI.Control.Context' denotes a 'property' where a 'class' was expected

I get the following error when trying to compile my project. The call to Context lies in a usercontrol. It works fine when called from a page, but how do I call it from a usercontrol?

private User _currentUser = new User(Context.User.Identity.Name);

'System.Web.UI.Control.Context' denotes a 'property' where a 'class' was expected


Firefox - The browser you can trust
0
notefrag
2/10/2004 8:25:56 AM
asp.net.security 27051 articles. 1 followers. Follow

2 Replies
918 Views

Similar Articles

[PageSpeed] 26

Update:

private User _currentUser = new User(Context.User.Identity.Name);
Is declared inside the class, not in a function. Like:
public class Someclass : System.Web.UI.UserControl

{
private User _currentUser = new User(Context.User.Identity.Name);
private void Page_Load(object sender, System.EventArgs e)
{
}
}

Firefox - The browser you can trust
0
notefrag
2/10/2004 9:04:10 AM
try HttpContext.Current.User.Identity.Name
Best regards,

Ivan Andrade
0
roberot
2/10/2004 10:49:49 AM
Reply:

Similar Artilces:

''''''''''''''''''''
Name: haznen Email: haznenatyahoodotcom Product: Gran Paradiso Alpha 8 Summary: '''''''''''''''''''' Comments: '''''''''''''''''''''''''''''''''''' Browser Details: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9a1) Gecko/20061204 UGES/1.7.2.0 GranParadiso/3.0a1 From URL: http://www.mozilla.org/projects/granparadiso/ Note to readers: Hendrix gives...

'''''
Name: mario Email: ramar17atfastwebnetdotit Product: Gran Paradiso Alpha 2 Summary: ''''' Comments: K: Browser Details: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9a2) Gecko/20070206 GranParadiso/3.0a2 ...

CS0118: 'System.Web.UI.WebControls.DataGridItem.DataItem' denotes a 'property' where a 'method' was expected
Hai .....,            In my datagrid, I would to display information using this ItemTemplate tag. But when i execute my page, I get the following error:CS0118: 'System.Web.UI.WebControls.DataGridItem.DataItem' denotes a 'property' where a 'method' was expected            In VB.NET, it is working perfectly but in C# it's not. I know to display data using DataBinder.Eval(Container.DataItem, "Field"), but would like Container.DataItem("Field") to work. Regards,HemantThanx and Regar...

System.Web.UI.Page.Request' denotes a 'property' where a 'method; was expected
i have create a datalist that displays book titles once click the hiperlink takes you to an edit page. the hyperlink looks like this. <asp:hyperlink id="link" Runat="server" Text='<%#DataBinder.Eval(Container.DataItem, "Title" )%>' NavigateURL='<%# Request.ApplicationPath + "/edit.aspx?id=" + DataBinder.Eval(Container.DataItem, "ref_id" ) %>'/> my problem is as follow when i get to the edit page. instead of displaying one record at a time it displays all records one after the other one. I have tried to use the follow...

'do' won't 'do' if '/'
Greetings to All from Au, Have a NetWare Perl 5.8.4 and wanted to tweak File\Spec\NW.pm to try and standardise on '/' separators. If I run a test script (t/uni/lower.t) with an unmodified NW.pm, it calls t/uni/case.pl, that, in case.pl, (when the path separators are '\'), the $file is '..\lib\unicore\To\Lower.pl' and the following code portion works, with $simple getting a returned table: sub casetest { my ($base, $spec, $func) = @_; my $file = File::Spec->catfile(File::Spec->catdir(File::Spec->updir, "lib", &qu...

'''
Name: L Lachowsky Email: e2brutus_10atyahoodotcom Product: Firefox Summary: ''' Comments: why duddn this surprise me... I change default server from IE to Mozilla, and then i get error messages. well, shud I decide to not get on my computer with Mozilla..or shud I risk security breeches with IE....hmmm at least i can get on the internet with IE Browser Details: Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.5) Gecko/2008120122 Firefox/3.0.5 From URL: http://hendrix.mozilla.org/ Note to readers: Hendrix gives no expectation of a response to this fee...

'System.Web.UI.IDataItemContainer.DataItem' is a 'property' but is used like a 'method'
On the line "<%# Container.DataItem("BlogID") %>", I get the error listed in the title of this post. I'm not sure why, I use this same for on other pages to get data from a database and I don't get this error.         <asp:GridView ID="GridView1"         runat="server"         AutoGenerateColumns="False"         DataKeyNames="BlogID"        D...

Cast from type ''''DBNull'''' to type ''''String'''' is not valid.
How do I avoid getting this error: Cast from type ''''DBNull'''' to type ''''String'''' is not valid. I am trying to get values from the database into a form for updating using a Datareader, SQL is set to allow nulls for certain fields as they are not required but the only way I can get the form to display is by adding a space in SQL. Is there another way around this? Check if it is equal to DBNull.Value first and if it is, don't do the cast.Stanley Tan theSpoke Blog Where in the code does it need to go? I am using the following and it's the profile that isn't always requi...

'System.Web.UI.WebControls.DataListItem.DataItem' is a 'property' but is used like a 'method'
 HI I have a datalist with OnItemDataBoundI get the following error when I try to get the DataItem 'System.Web.UI.WebControls.DataListItem.DataItem' is a 'property' but is used like a 'method' , any idea what's wrong with the line ?  public void Item_Bound(object sender, DataListItemEventArgs e)    {        Label originalPriceLabel;        if (e.Item.ItemType == ListItemType.Item | e.Item.ItemType == ListItemType.AlternatingItem)        {    &n...

''System.Web.UI.UserControl' does not have a public property named 'Title'.
The controls work but I cannot view them in designer I get an error: Error 1 Content1:Type 'System.Web.UI.UserControl' does not have a public property named 'Title'. D:\asp.net\Atlas\SampleWebSite\ModalPopup\ModalPopup.aspx D:\...\SampleWebSite\ I saw another post that said to rebuild, but I tried that and it didn't work. thanks! Nevermind... found the answer to remove the collapible panels.  Wait until next release. ...

'or' or 'union'
Hello I was just wondering, in general what is better to use, an 'or' clause in a select or a 'union' to join two selects together. Do both statements create work tables? Many thanks Alex I think OR will be better than union. because suppose u have 3 tables and using OR u can join table a and table b and table c so each table will have only one read. but using union you will join table a and table b and in another query of union u will use table (a or b) and table c so ur one read is more in union . Ramdas Alex Cheung wrote: > Hello > >...

'b'..'a'
Hello. I'm using defferent 5.6.0's for Win32. I wonder wheter following behaviour is intentional or not: d:\>perl -e "print 'b'..'c'" bc d:\>perl -e "print 'b'..'a'" bcdefghijklmnopqrstuvwxyz I expected empty list in latter case, like in perl -e "print 'bb'..'a'" <!ENTITY Vadim REALLIFE "Vadim V.Konovalov, St.Petersburg, Russia"> &Vadim; On Wed, Sep 20, 2000 at 03:14:41PM +0400, Konovalov, Vadim wrote: > Hello. > > I'm using defferent 5.6.0'...

'IN' Clause or 'OR'
Hello, [1]: select * from TABLEA where COL1 IN('value1','value2''valu3'....) [2]:select * from TABLEA where COL1 = 'value1' OR COL1= 'value2' OR COL1='valu3'. TABLEA is a huge table and it has non-clustered index on COL1. Among the above 2 queries, which query will give me the better performance or fast response and WHY? What is the difference between 'IN' and 'OR' clauses as for as Sybase Optimization is concerned. Which is the better one to be used on huge tables. Thanks. Mac An IN list is treated ...

Error: Cannot convert type 'System.Web.UI.Control' to 'System.Web.UI.WebControls.ButtonField'
Hello, I am getting the following error during compiliation. Any suggestions to fix it. Thanks. Cannot convert type 'System.Web.UI.Control' to 'System.Web.UI.WebControls.ButtonField' protected void gvEvents_RowCommand(Object sender, GridViewCommandEventArgs e) { if (e.CommandName == "Select") { int index = Convert.ToInt32(e.CommandArgument); GridViewRow selectedRow = gvEvents.Rows[index]; string sID; ButtonField btn; if (selectedRow.RowType == DataControlRowType.DataRow) { sID = ((ButtonField)selectedRow.FindControl("ID")).DataTextFi...

Web resources about - 'System.Web.UI.Control.Context' denotes a 'property' where a 'class' was expected - asp.net.security

Resources last updated: 12/14/2015 12:55:13 AM